Popular Functions & Graphing Problems

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Popular Functions & Graphing Problems

slope intercept of 5x+y=-5	slope\:intercept\:5x+y=-5
g(x)=x^2-2x+5	g(x)=x^{2}-2x+5
f(t)=3cos(t)	f(t)=3\cos(t)
f(x)=sin^2(x)+tan^2(x)+cot^2(x)	f(x)=\sin^{2}(x)+\tan^{2}(x)+\cot^{2}(x)
y=(x+2)^3	y=(x+2)^{3}
f(x)=(x^2+1)/(x-1)	f(x)=\frac{x^{2}+1}{x-1}
f(x)=2^{(((log_{2}(x)))/(x-1))}	f(x)=2^{(\frac{(\log_{2}(x))}{x-1})}
f(x)=(2(x^2-9))/(x^2-4)	f(x)=\frac{2(x^{2}-9)}{x^{2}-4}
f(n)=n+3	f(n)=n+3
y= 1/(cos(x))	y=\frac{1}{\cos(x)}
f(x)=8x+arctan(6x)	f(x)=8x+\arctan(6x)
inverse of f(x)=(e^{4x})/(3+e^{4x)}	inverse\:f(x)=\frac{e^{4x}}{3+e^{4x}}
f(x)=2x^2-12x+14	f(x)=2x^{2}-12x+14
f(x)=cos(x)+2	f(x)=\cos(x)+2
f(x)=(2x)/((x^2-5x+6)(x^2+2)^2)	f(x)=\frac{2x}{(x^{2}-5x+6)(x^{2}+2)^{2}}
f(x)=1+x-x^2	f(x)=1+x-x^{2}
f(x)=3x^3+6x^2+7x	f(x)=3x^{3}+6x^{2}+7x
y=sin(x-pi)	y=\sin(x-π)
y=x^2+12x+40	y=x^{2}+12x+40
y=-3cos(2x)	y=-3\cos(2x)
f(x)=sqrt(x-2)+3	f(x)=\sqrt{x-2}+3
f(x)=25x^2+36	f(x)=25x^{2}+36
line 7x-8y=0	line\:7x-8y=0
f(x)=cos(2x)*cos(x)	f(x)=\cos(2x)\cdot\:\cos(x)
f(x)=(2-x)(x-3)x	f(x)=(2-x)(x-3)x
f(x)=(2x)/(x^2-16)	f(x)=\frac{2x}{x^{2}-16}
f(x)=(x^3+3)2	f(x)=(x^{3}+3)2
f(x)=x+20	f(x)=x+20
f(x)=sin^4(3x)	f(x)=\sin^{4}(3x)
f(x)=x^2+3x+1/4	f(x)=x^{2}+3x+\frac{1}{4}
y=4^x-1	y=4^{x}-1
y=xe^{-2x}	y=xe^{-2x}
f(x)=2^{x-5}	f(x)=2^{x-5}
critical points of x^4-x^2	critical\:points\:x^{4}-x^{2}
f(x)=x^2+10x+1	f(x)=x^{2}+10x+1
f(x)=(3x+1)/(x-2)	f(x)=\frac{3x+1}{x-2}
f(y)=y+4	f(y)=y+4
f(x)=sqrt(6x-x^2)	f(x)=\sqrt{6x-x^{2}}
y=2x^2+8x+5	y=2x^{2}+8x+5
f(x)=sin(x)+2	f(x)=\sin(x)+2
f(x)= 1/2 x+7	f(x)=\frac{1}{2}x+7
g(x)=x^2+sin(x)	g(x)=x^{2}+\sin(x)
g(x)=-x^2-7x+8	g(x)=-x^{2}-7x+8
f(x)=x^2+3x+8	f(x)=x^{2}+3x+8
domain of f(x)= 7/(x-4)	domain\:f(x)=\frac{7}{x-4}
f(x)=log_{2}(x+8)	f(x)=\log_{2}(x+8)
f(x)=4-\|x\|	f(x)=4-\left\|x\right\|
f(y)=ln(-e^{-y})	f(y)=\ln(-e^{-y})
f(x)=(x-5)/(x+2)	f(x)=\frac{x-5}{x+2}
y=\|x+5\|	y=\left\|x+5\right\|
f(x)=7x-9	f(x)=7x-9
f(x)=x^2-5x-24	f(x)=x^{2}-5x-24
y=(x-1)/(x^2)	y=\frac{x-1}{x^{2}}
y=-0.005x^2+x+5	y=-0.005x^{2}+x+5
f(t)=(log_{10}(t))/(log_{8)(t)}	f(t)=\frac{\log_{10}(t)}{\log_{8}(t)}
slope of y=11x-5	slope\:y=11x-5
f(x)=x^2+8x+9	f(x)=x^{2}+8x+9
f(x)=x^3-6x^2+10	f(x)=x^{3}-6x^{2}+10
f(x)=-x^2+6x-11	f(x)=-x^{2}+6x-11
f(x)=x^2+8x-12	f(x)=x^{2}+8x-12
f(x)=(3/4 x^3-2x^2+x/4-6)(2x^2-2x+4)	f(x)=(\frac{3}{4}x^{3}-2x^{2}+\frac{x}{4}-6)(2x^{2}-2x+4)
f(x)=sqrt(x)+6	f(x)=\sqrt{x}+6
f(x)= x/(1+x)	f(x)=\frac{x}{1+x}
y= 2/(sqrt(x))	y=\frac{2}{\sqrt{x}}
g(x)=2^x	g(x)=2^{x}
f(x)=ln(e^x-e^{-x})	f(x)=\ln(e^{x}-e^{-x})
critical points of (x^2-9)^6	critical\:points\:(x^{2}-9)^{6}
y= 1/(2x-4)	y=\frac{1}{2x-4}
f(x)=(ln(x))/(e^x)	f(x)=\frac{\ln(x)}{e^{x}}
f(x)=2x+13	f(x)=2x+13
f(x)=\|x+6\|	f(x)=\left\|x+6\right\|
f(x)=-2x^2+2	f(x)=-2x^{2}+2
f(x)=2x^2-5x-2	f(x)=2x^{2}-5x-2
y=-x^2+2x+5	y=-x^{2}+2x+5
y=x^8	y=x^{8}
r(θ)=4csc(θ)	r(θ)=4\csc(θ)
f(x)=tan(x+pi/2)	f(x)=\tan(x+\frac{π}{2})
range of f(x)=0	range\:f(x)=0
critical points of sqrt(4-x^2)	critical\:points\:\sqrt{4-x^{2}}
f(x)=3^x+4	f(x)=3^{x}+4
g(x)=x^2-9	g(x)=x^{2}-9
f(x)=(-2x+8)/(x^2-4x)	f(x)=\frac{-2x+8}{x^{2}-4x}
g(x)=2x	g(x)=2x
f(x)=(2x^4-1)(5x^3+6x)	f(x)=(2x^{4}-1)(5x^{3}+6x)
y=\sqrt[3]{x-1}	y=\sqrt[3]{x-1}
f(x)= 1/3 x^3-x^2-3x+4	f(x)=\frac{1}{3}x^{3}-x^{2}-3x+4
f(x)=sqrt(x/2)	f(x)=\sqrt{\frac{x}{2}}
y=x^3-3x^2-9x+5	y=x^{3}-3x^{2}-9x+5
f(x)=x^2-14x+53	f(x)=x^{2}-14x+53
range of f(x)=(x+1)/(x-1)	range\:f(x)=\frac{x+1}{x-1}
y=10x+7	y=10x+7
f(x)=sin(x)+2x+1	f(x)=\sin(x)+2x+1
f(x)=(sin(x))/(2x)	f(x)=\frac{\sin(x)}{2x}
f(x)=sin^2(x)\times cos^2(x)	f(x)=\sin^{2}(x)\times\:\cos^{2}(x)
f(x)=csc(3x)	f(x)=\csc(3x)
y=-log_{3}(x)	y=-\log_{3}(x)
f(x)=(x-3)/(x^2-4)	f(x)=\frac{x-3}{x^{2}-4}
f(x)=15x	f(x)=15x
f(x)=18x	f(x)=18x
f(x)=(1-x)^2	f(x)=(1-x)^{2}

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