What is the extreme f(x)=-0.03x^2+380x-100000 ?

The extreme f(x)=-0.03x^2+380x-100000 is Maximum(19000/3 ,1103333.33333…)

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extreme f(x)=-0.03x^2+380x-100000

extreme points

f (x) = - 0.03 x^{2} + 380 x - 100000

Maximum (\frac{19000}{3}, 1103333.33333 \dots)

Solution steps

f^{'} (x) = - 0.06 x + 380

Find intervals:

Increasing

: - \infty < x < \frac{19000}{3},

Decreasing

: \frac{19000}{3} < x < \infty

Plug

x = \frac{19000}{3}

into

- 0.03 x^{2} + 380 x - 100000 : 1103333.33333 \dots

Maximum (\frac{19000}{3}, 1103333.33333 \dots)

f (x, y) = x^{2} + 2 x + y^{2} - 2 y

f (x) = x y - x - 2

f (x, y) = x e y^{2} + y ln (x)

y = - x^{2} - x - 5

f (x) = 3 x^{4} - 8 x^{3} + 6 x^{2} - 9

What is the extreme f(x)=-0.03x^2+380x-100000 ?
The extreme f(x)=-0.03x^2+380x-100000 is Maximum(19000/3 ,1103333.33333…)