What is the extreme f(x,y)=x^2-2x+4y-y^2 ?

The extreme f(x,y)=x^2-2x+4y-y^2 is Saddle(1,2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=x^2-2x+4y-y^2

extreme points

f (x, y) = x^{2} - 2 x + 4 y - y^{2}

Saddle (1, 2)

Solution steps

Find the critical points:

(1, 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = - 4

Check the sign of at each critical point

Check critical point

(1, 2) :

Saddle

Saddle (1, 2)

f (x) = 21 - 12 x - \frac{12}{x}

f (x) = \frac{2 x - 1}{x}

y = (\frac{x}{x + 5})

f (x) = 2 x^{2} - 4 x - 6

f (x, y) = 2 x^{2} + 4 x y

What is the extreme f(x,y)=x^2-2x+4y-y^2 ?
The extreme f(x,y)=x^2-2x+4y-y^2 is Saddle(1,2)