What is the derivative of ln(2x^2) ?

The derivative of ln(2x^2) is 2/x

What is the first derivative of ln(2x^2) ?

The first derivative of ln(2x^2) is 2/x

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derivative of

ln (2 x^{2})

\frac{2}{x}

Solution steps

\frac{d}{d x} (ln (2 x^{2}))

Apply the chain rule:

\frac{1}{2 x ^{2}} \frac{d}{d x} (2 x^{2})

= \frac{1}{2 x ^{2}} \frac{d}{d x} (2 x^{2})

\frac{d}{d x} (2 x^{2}) = 4 x

= \frac{1}{2 x ^{2}} \cdot 4 x

Simplify

\frac{1}{2 x ^{2}} \cdot 4 x : \frac{2}{x}

= \frac{2}{x}

\frac{1}{( r + t )}

\frac{1}{( 2 x )}

\frac{( 4 - x )}{sin ^{2} ( x )}

∣ x + 2 ∣ - 2

\frac{d}{df} (f (1) + f (- 2))

What is the derivative of ln(2x^2) ?
The derivative of ln(2x^2) is 2/x
What is the first derivative of ln(2x^2) ?
The first derivative of ln(2x^2) is 2/x