What is the derivative of 1/((2x)) ?

The derivative of 1/((2x)) is -1/(2x^2)

What is the first derivative of 1/((2x)) ?

The first derivative of 1/((2x)) is -1/(2x^2)

derivative of

\frac{1}{( 2 x )}

- \frac{1}{2 x ^{2}}

Solution steps

\frac{d}{d x} (\frac{1}{2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{1}{2} \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{2} (- 1 \cdot x^{- 1 - 1})

Simplify

\frac{1}{2} (- 1 \cdot x^{- 1 - 1}) : - \frac{1}{2 x ^{2}}

= - \frac{1}{2 x ^{2}}

\frac{( 4 - x )}{sin ^{2} ( x )}

∣ x + 2 ∣ - 2

\frac{d}{df} (f (1) + f (- 2))

y = lo g_{10} (sin^{2} (x))

\frac{sin ^{2} ( x )}{x}

What is the derivative of 1/((2x)) ?
The derivative of 1/((2x)) is -1/(2x^2)
What is the first derivative of 1/((2x)) ?
The first derivative of 1/((2x)) is -1/(2x^2)