What is the derivative of 1/((r+t)) ?

The derivative of 1/((r+t)) is -1/((r+t)^2)

What is the first derivative of 1/((r+t)) ?

The first derivative of 1/((r+t)) is -1/((r+t)^2)

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derivative of

\frac{1}{( r + t )}

- \frac{1}{( r + t ) ^{2}}

Solution steps

\frac{d}{d r} (\frac{1}{r + t})

Treat

t

as a constant

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d r} ((r + t)^{- 1})

Apply the chain rule:

- \frac{1}{( r + t ) ^{2}} \frac{d}{d r} (r + t)

= - \frac{1}{( r + t ) ^{2}} \frac{d}{d r} (r + t)

\frac{d}{d r} (r + t) = 1

= - \frac{1}{( r + t ) ^{2}} \cdot 1

Simplify

= - \frac{1}{( r + t ) ^{2}}

d er i v a t i v e \frac{1}{( 2 x )}

d er i v a t i v e \frac{( 4 - x )}{sin ^{2} ( x )}

d er i v a t i v e ∣ x + 2 ∣ - 2

\frac{d}{df} (f (1) + f (- 2))

d er i v a t i v e y = lo g_{10} (sin^{2} (x))

What is the derivative of 1/((r+t)) ?
The derivative of 1/((r+t)) is -1/((r+t)^2)
What is the first derivative of 1/((r+t)) ?
The first derivative of 1/((r+t)) is -1/((r+t)^2)