What are the solutions to the equation 5n^2+40n=5n ?

The solutions to the equation 5n^2+40n=5n are n=0,n=-7

Find the zeros of 5n^2+40n=5n

The zeros of 5n^2+40n=5n are n=0,n=-7

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5 n^{2} + 40 n = 5 n

n = 0, n = - 7

Solution steps

5 n^{2} + 40 n = 5 n

Move

5 n

to the left side

5 n^{2} + 35 n = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 35 \pm 3 5 ^{2} - 4 \cdot 5 \cdot 0}{2 \cdot 5}

3 5^{2} - 4 \cdot 5 \cdot 0 = 35

n_{1, 2} = \frac{- 35 \pm 35}{2 \cdot 5}

Separate the solutions

n_{1} = \frac{- 35 + 35}{2 \cdot 5}, n_{2} = \frac{- 35 - 35}{2 \cdot 5}

n = \frac{- 35 + 35}{2 \cdot 5} : 0

n = \frac{- 35 - 35}{2 \cdot 5} : - 7

The solutions to the quadratic equation are:

n = 0, n = - 7

29000 = 11.8 \cdot 7.1 \cdot (\frac{x}{1000})^{2}

5 x^{2} - 40 x - 75 = 0

1 6^{3}

\frac{( a ^{4} - b ^{4} )}{( a - b )}

\frac{8 ! 7 !}{9 ! 5 !}

What are the solutions to the equation 5n^2+40n=5n ?
The solutions to the equation 5n^2+40n=5n are n=0,n=-7
Find the zeros of 5n^2+40n=5n
The zeros of 5n^2+40n=5n are n=0,n=-7