5=15^{2-0.01q}

Lösung

5 = 1 5^{2 - 0.01 q}

q = \frac{ln ( 45 )}{0.01 ln ( 15 )}

Dezimale

q = 140.56838 \dots

Schritte zur Lösung

5 = 1 5^{2 - 0.01 q}

Wende Exponentenregel an

ln (5) = (2 - 0.01 q) ln (15)

Löse

ln (5) = (2 - 0.01 q) ln (15) : q = \frac{ln ( 45 )}{0.01 ln ( 15 )}

q = \frac{ln ( 45 )}{0.01 ln ( 15 )}

e^{x} - 6 e^{x} - 1 = 0

0 = 3 e^{3 x} (10 - 6 x) + e^{3 x} (- 6)

\frac{1}{5} = e^{- 3 t}

2 (3^{2 x}) + 7 (3^{x}) - 15 = 0

5^{2 x - 5} = 125