7^{3x^2}=49^{6x+2}

Lösung

7^{3 x^{2}} = 4 9^{6 x + 2}

x = \frac{2 ( 3 + 2 3 )}{3}, x = \frac{2 ( 3 - 2 3 )}{3}

Dezimale

x = 4.30940 \dots, x = - 0.30940 \dots

Schritte zur Lösung

7^{3 x^{2}} = 4 9^{6 x + 2}

Wende Exponentenregel an

3 x^{2} = 2 (6 x + 2)

Löse

3 x^{2} = 2 (6 x + 2) : x = \frac{2 ( 3 + 2 3 )}{3}, x = \frac{2 ( 3 - 2 3 )}{3}

x = \frac{2 ( 3 + 2 3 )}{3}, x = \frac{2 ( 3 - 2 3 )}{3}

9^{x} - 4 = 3^{x + 1}

e^{x} + 6 \cdot e^{- x} = 5

100 - 98 y + 980 (1 - e^{- 0.1 y}) = 0

4 e^{2 x} = 0

9 \cdot 2^{x - 1} = 2 \cdot 3^{x}