What are the solutions to the equation 0=3(x-4)^2-5 ?

The solutions to the equation 0=3(x-4)^2-5 are x=sqrt(5/3)+4,x=-sqrt(5/3)+4

Find the zeros of 0=3(x-4)^2-5

The zeros of 0=3(x-4)^2-5 are x=sqrt(5/3)+4,x=-sqrt(5/3)+4

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0 = 3 (x - 4)^{2} - 5

x = \frac{5}{3} + 4, x = - \frac{5}{3} + 4

Decimal Notation

x = 5.29099 \dots, x = 2.70900 \dots

Solution steps

0 = 3 (x - 4)^{2} - 5

Switch sides

3 (x - 4)^{2} - 5 = 0

Move

5

to the right side

3 (x - 4)^{2} = 5

Divide both sides by

3

(x - 4)^{2} = \frac{5}{3}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = \frac{5}{3} : x = \frac{5}{3} + 4

Solve

x - 4 = - \frac{5}{3} : x = - \frac{5}{3} + 4

The solutions to the quadratic equation are:

x = \frac{5}{3} + 4, x = - \frac{5}{3} + 4

1^{\frac{3}{2}}

x - 2 = 10 - 5 x

x^{4} - 8 x^{2} - 240

x^{2} + 55 = - 16 x

What are the solutions to the equation 0=3(x-4)^2-5 ?
The solutions to the equation 0=3(x-4)^2-5 are x=sqrt(5/3)+4,x=-sqrt(5/3)+4
Find the zeros of 0=3(x-4)^2-5
The zeros of 0=3(x-4)^2-5 are x=sqrt(5/3)+4,x=-sqrt(5/3)+4