What are the solutions to the equation -3x^2-6x+9=0 ?

The solutions to the equation -3x^2-6x+9=0 are x=-3,x=1

Find the zeros of -3x^2-6x+9=0

The zeros of -3x^2-6x+9=0 are x=-3,x=1

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- 3 x^{2} - 6 x + 9 = 0

x = - 3, x = 1

Solution steps

- 3 x^{2} - 6 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 3 ) \cdot 9}{2 ( - 3 )}

(- 6)^{2} - 4 (- 3) \cdot 9 = 12

x_{1, 2} = \frac{- ( - 6 ) \pm 12}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 12}{2 ( - 3 )}, x_{2} = \frac{- ( - 6 ) - 12}{2 ( - 3 )}

x = \frac{- ( - 6 ) + 12}{2 ( - 3 )} : - 3

x = \frac{- ( - 6 ) - 12}{2 ( - 3 )} : 1

The solutions to the quadratic equation are:

x = - 3, x = 1

6 b^{2 n + 1} + 5 b^{n + 1} - 6 b

3 p^{2} + 14 p + 8

4 x^{2} + 20 x + 25

\frac{2}{x + 2} \geq \frac{1}{x - 3}

0 = 3 x^{2} - 3

What are the solutions to the equation -3x^2-6x+9=0 ?
The solutions to the equation -3x^2-6x+9=0 are x=-3,x=1
Find the zeros of -3x^2-6x+9=0
The zeros of -3x^2-6x+9=0 are x=-3,x=1