What are the solutions to the equation 14=5x^2-x-4 ?

The solutions to the equation 14=5x^2-x-4 are x=2,x=-9/5

Find the zeros of 14=5x^2-x-4

The zeros of 14=5x^2-x-4 are x=2,x=-9/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

14 = 5 x^{2} - x - 4

x = 2, x = - \frac{9}{5}

Decimal Notation

x = 2, x = - 1.8

Solution steps

14 = 5 x^{2} - x - 4

Switch sides

5 x^{2} - x - 4 = 14

Move

14

to the left side

5 x^{2} - x - 18 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 ( - 18 )}{2 \cdot 5}

(- 1)^{2} - 4 \cdot 5 (- 18) = 19

x_{1, 2} = \frac{- ( - 1 ) \pm 19}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 19}{2 \cdot 5}, x_{2} = \frac{- ( - 1 ) - 19}{2 \cdot 5}

x = \frac{- ( - 1 ) + 19}{2 \cdot 5} : 2

x = \frac{- ( - 1 ) - 19}{2 \cdot 5} : - \frac{9}{5}

The solutions to the quadratic equation are:

x = 2, x = - \frac{9}{5}

0 = 3 (x - 4)^{2} - 5

1^{\frac{3}{2}}

x - 2 = 10 - 5 x

x^{4} - 8 x^{2} - 240

What are the solutions to the equation 14=5x^2-x-4 ?
The solutions to the equation 14=5x^2-x-4 are x=2,x=-9/5
Find the zeros of 14=5x^2-x-4
The zeros of 14=5x^2-x-4 are x=2,x=-9/5