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Popular Trigonometria >

solvefor x,u=cos(x^2y)

Solução

resolver para

x, u = cos (x^{2} y)

Solução

x = \frac{arccos ( u ) + 2 πn}{y}, x = - \frac{arccos ( u ) + 2 πn}{y}, x = \frac{- arccos ( u ) + 2 πn}{y}, x = - \frac{- arccos ( u ) + 2 πn}{y}

Passos da solução

u = cos (x^{2} y)

Trocar lados

cos (x^{2} y) = u

Aplique as propriedades trigonométricas inversas

cos (x^{2} y) = u

Soluções gerais para

cos (x^{2} y) = u

cos (x) = a \Rightarrow x = arccos (a) + 2 πn, x = - arccos (a) + 2 πn

x^{2} y = arccos (u) + 2 πn, x^{2} y = - arccos (u) + 2 πn

x^{2} y = arccos (u) + 2 πn, x^{2} y = - arccos (u) + 2 πn

Resolver

x^{2} y = arccos (u) + 2 πn : x = \frac{arccos ( u ) + 2 πn}{y}, x = - \frac{arccos ( u ) + 2 πn}{y}; y \neq = 0

x^{2} y = arccos (u) + 2 πn

Dividir ambos os lados por

y; y \neq = 0

x^{2} y = arccos (u) + 2 πn

Dividir ambos os lados por

y; y \neq = 0

\frac{x ^{2} y}{y} = \frac{arccos ( u )}{y} + \frac{2 πn}{y}; y \neq = 0

Simplificar

x^{2} = \frac{arccos ( u )}{y} + \frac{2 πn}{y}; y \neq = 0

x^{2} = \frac{arccos ( u )}{y} + \frac{2 πn}{y}; y \neq = 0

Para

x^{2} = f (a)

as soluções são

x = f (a), - f (a)

x = \frac{arccos ( u )}{y} + \frac{2 πn}{y}, x = - \frac{arccos ( u )}{y} + \frac{2 πn}{y}; y \neq = 0

Simplificar

\frac{arccos ( u )}{y} + \frac{2 πn}{y} : \frac{arccos ( u ) + 2 πn}{y}

\frac{arccos ( u )}{y} + \frac{2 πn}{y}

Combinar as frações usando o mínimo múltiplo comum:

\frac{arccos ( u ) + 2 πn}{y}

Aplicar a regra

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{arccos ( u ) + 2 πn}{y}

= \frac{arccos ( u ) + 2 πn}{y}

Simplificar

- \frac{arccos ( u )}{y} + \frac{2 πn}{y} : - \frac{arccos ( u ) + 2 πn}{y}

- \frac{arccos ( u )}{y} + \frac{2 πn}{y}

Combinar as frações usando o mínimo múltiplo comum:

\frac{arccos ( u ) + 2 πn}{y}

Aplicar a regra

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{arccos ( u ) + 2 πn}{y}

= - \frac{2 πn + arccos ( u )}{y}

= - \frac{arccos ( u ) + 2 πn}{y}

x = \frac{arccos ( u ) + 2 πn}{y}, x = - \frac{arccos ( u ) + 2 πn}{y}; y \neq = 0

Resolver

x^{2} y = - arccos (u) + 2 πn : x = \frac{- arccos ( u ) + 2 πn}{y}, x = - \frac{- arccos ( u ) + 2 πn}{y}; y \neq = 0

x^{2} y = - arccos (u) + 2 πn

Dividir ambos os lados por

y; y \neq = 0

x^{2} y = - arccos (u) + 2 πn

Dividir ambos os lados por

y; y \neq = 0

\frac{x ^{2} y}{y} = - \frac{arccos ( u )}{y} + \frac{2 πn}{y}; y \neq = 0

Simplificar

x^{2} = - \frac{arccos ( u )}{y} + \frac{2 πn}{y}; y \neq = 0

x^{2} = - \frac{arccos ( u )}{y} + \frac{2 πn}{y}; y \neq = 0

Para

x^{2} = f (a)

as soluções são

x = f (a), - f (a)

x = - \frac{arccos ( u )}{y} + \frac{2 πn}{y}, x = - - \frac{arccos ( u )}{y} + \frac{2 πn}{y}; y \neq = 0

Simplificar

- \frac{arccos ( u )}{y} + \frac{2 πn}{y} : \frac{- arccos ( u ) + 2 πn}{y}

- \frac{arccos ( u )}{y} + \frac{2 πn}{y}

Combinar as frações usando o mínimo múltiplo comum:

\frac{- arccos ( u ) + 2 πn}{y}

Aplicar a regra

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- arccos ( u ) + 2 πn}{y}

= \frac{- arccos ( u ) + 2 πn}{y}

Simplificar

- - \frac{arccos ( u )}{y} + \frac{2 πn}{y} : - \frac{- arccos ( u ) + 2 πn}{y}

- - \frac{arccos ( u )}{y} + \frac{2 πn}{y}

Combinar as frações usando o mínimo múltiplo comum:

\frac{- arccos ( u ) + 2 πn}{y}

Aplicar a regra

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{- arccos ( u ) + 2 πn}{y}

= - \frac{2 πn - arccos ( u )}{y}

= - \frac{- arccos ( u ) + 2 πn}{y}

x = \frac{- arccos ( u ) + 2 πn}{y}, x = - \frac{- arccos ( u ) + 2 πn}{y}; y \neq = 0

x = \frac{arccos ( u ) + 2 πn}{y}, x = - \frac{arccos ( u ) + 2 πn}{y}, x = \frac{- arccos ( u ) + 2 πn}{y}, x = - \frac{- arccos ( u ) + 2 πn}{y}

Gráfico

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