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受欢迎的三角函数 >

solvefor t,0=8sin((pit)/(12))+32

解答

求解

t, 0 = 8 sin (\frac{π t}{12}) + 32

解答

t \in R 无解

求解步骤

0 = 8 sin (\frac{π t}{12}) + 32

交换两边

8 sin (\frac{π t}{12}) + 32 = 0

将

32

到右边

8 sin (\frac{π t}{12}) + 32 = 0

两边减去

32

8 sin (\frac{π t}{12}) + 32 - 32 = 0 - 32

化简

8 sin (\frac{π t}{12}) = - 32

8 sin (\frac{π t}{12}) = - 32

两边除以

8

8 sin (\frac{π t}{12}) = - 32

两边除以

8

\frac{8 sin ( \frac{π t}{12} )}{8} = \frac{- 32}{8}

化简

\frac{8 sin ( \frac{π t}{12} )}{8} = \frac{- 32}{8}

化简

\frac{8 sin ( \frac{π t}{12} )}{8} : sin (\frac{π t}{12})

\frac{8 sin ( \frac{π t}{12} )}{8}

数字相除:

\frac{8}{8} = 1

= sin (\frac{π t}{12})

化简

\frac{- 32}{8} : - 4

\frac{- 32}{8}

使用分式法则:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{32}{8}

数字相除:

\frac{32}{8} = 4

= - 4

sin (\frac{π t}{12}) = - 4

sin (\frac{π t}{12}) = - 4

sin (\frac{π t}{12}) = - 4

- 1 \leq sin (x) \leq 1

t \in R 无解

作图

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