sec(x)= 1/3

解答

sec (x) = \frac{1}{3}

x \in R 无解

求解步骤

sec (x) = \frac{1}{3}

sec (x) \leq - 1 or sec (x) \geq 1

x \in R 无解

so l v e f or x, u = cos (x^{2} y)

6 sin^{2} (x) - sin (x) cos (x) - 2 cos^{2} (x) = 0

tan (θ) = \frac{20 ( 9.8 )}{25}

so l v e f or t, 0 = 8 sin (\frac{π t}{12}) + 32

2 sin^{2} (x) + sin (x) - 1 = 0, 0 \leq x < 2 π