What is the extreme f(x,y)=-2x^2-2y^2-4xy+5x+4y ?

The extreme f(x,y)=-2x^2-2y^2-4xy+5x+4y is None

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extreme f(x,y)=-2x^2-2y^2-4xy+5x+4y

extreme points

f (x, y) = - 2 x^{2} - 2 y^{2} - 4 x y + 5 x + 4 y

None

Solution steps

Find the critical points:

None

- 2 x^{2} - 2 y^{2} - 4 x y + 5 x + 4 y

has no critical points, therefore there are no extreme points

None

f (x) = (x^{2} + x)^{\frac{2}{3}}

(x^{2} + 12) (4 - x^{2})

f (x y) = x^{3} + y^{3} + 2 x^{2} + 4 y^{2} + 6

f (x) = 2 x - 4 x

f (x) = \frac{1}{2} x^{3} - 3 x y + 3 y^{2} - x

What is the extreme f(x,y)=-2x^2-2y^2-4xy+5x+4y ?
The extreme f(x,y)=-2x^2-2y^2-4xy+5x+4y is None