What is the extreme f(x,y)=-3x^2+7xy-4y^2+x+y ?

The extreme f(x,y)=-3x^2+7xy-4y^2+x+y is Saddle(-15,-13)

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extreme f(x,y)=-3x^2+7xy-4y^2+x+y

extreme points

f (x, y) = - 3 x^{2} + 7 x y - 4 y^{2} + x + y

Saddle (- 15, - 13)

Solution steps

Find the critical points:

(- 15, - 13)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 8

D (x, y) = - 1

Check the sign of at each critical point

Check critical point

(- 15, - 13) :

Saddle

Saddle (- 15, - 13)

x^{4} + x^{3} - 6 x^{2}

f (x) = x^{3} - 27 x + 7

f (x) = 2 x^{3} - 9 x^{2} + 7 x + 6

f (x) = \frac{x - 5}{x ^{2}}

f (x) = (x + 1) (x - 1)^{2}

What is the extreme f(x,y)=-3x^2+7xy-4y^2+x+y ?
The extreme f(x,y)=-3x^2+7xy-4y^2+x+y is Saddle(-15,-13)