extreme f(x)=3x^2-18x+24

Lösung

extrempunkte

f (x) = 3 x^{2} - 18 x + 24

Minimum (3, - 3)

Schritte zur Lösung

f^{'} (x) = 6 x - 18

Intervalle finden:

Absteigend

: - \infty < x < 3,

Ansteigend

: 3 < x < \infty

Stecke

x = 3

3 x^{2} - 18 x + 24 : - 3

Minimum (3, - 3)

e x t re m e f (x, y) = - 2 x^{2} - 2 y^{2} - 4 x y + 5 x + 4 y

e x t re m e f (x) = (x^{2} + x)^{\frac{2}{3}}

e x t re m e f (x y) = x^{3} + y^{3} + 2 x^{2} + 4 y^{2} + 6

e x t re m e f (x) = \frac{1}{2} x^{3} - 3 x y + 3 y^{2} - x

e x t re m e \frac{x ^{2}}{( x - 1 ) ^{2}}