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Beliebt Funktionen >

extreme f(x)=-8x^2+x^4

Lösung

extrempunkte

f (x) = - 8 x^{2} + x^{4}

Lösung

Minimum (- 2, - 16), Maximum (0, 0), Minimum (2, - 16)

Schritte zur Lösung

f^{'} (x) = - 16 x + 4 x^{3}

Intervalle finden:

Absteigend

: - \infty < x < - 2,

Ansteigend

: - 2 < x < 0,

Absteigend

: 0 < x < 2,

Ansteigend

: 2 < x < \infty

Stecke

x = - 2

in

- 8 x^{2} + x^{4} : - 16

Minimum (- 2, - 16)

Stecke

x = 0

in

- 8 x^{2} + x^{4} : 0

Maximum (0, 0)

Stecke

x = 2

in

- 8 x^{2} + x^{4} : - 16

Minimum (2, - 16)

Minimum (- 2, - 16), Maximum (0, 0), Minimum (2, - 16)

Graph

Beliebte Beispiele

extreme f(t)=108t-t^3,-7<= t<infinity

e x t re m e f (t) = 108 t - t^{3}, - 7 \leq t < \infty

extreme f(x)=2ln(x)1+3ln(x)2+3ln(x)3

e x t re m e f (x) = 2 ln (x) 1 + 3 ln (x) 2 + 3 ln (x) 3

extreme f(x)=ln(x),0<x<= 4

e x t re m e f (x) = ln (x), 0 < x \leq 4

extreme f(x)=x^5-x^3+1

e x t re m e f (x) = x^{5} - x^{3} + 1

extreme y= x/(x^2+16)

e x t re m e y = \frac{x}{x ^{2} + 16}