What is the derivative of 1/(t^2) ?

The derivative of 1/(t^2) is -2/(t^3)

What is the first derivative of 1/(t^2) ?

The first derivative of 1/(t^2) is -2/(t^3)

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derivative of

\frac{1}{t ^{2}}

- \frac{2}{t ^{3}}

Solution steps

\frac{d}{d t} (\frac{1}{t ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d t} (t^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= - 2 t^{- 2 - 1}

Simplify

- 2 t^{- 2 - 1} : - \frac{2}{t ^{3}}

= - \frac{2}{t ^{3}}

\int_{0}^{1} x \cdot e^{x} d x

d er i v a t i v e y = x - x^{3}

\int \frac{x ^{2} - 5}{( x + 1 ) ^{3}} d x

\int_{0}^{π} 20 sin^{4} (x) d x

\int 3 x cos (3 x) d x

What is the derivative of 1/(t^2) ?
The derivative of 1/(t^2) is -2/(t^3)
What is the first derivative of 1/(t^2) ?
The first derivative of 1/(t^2) is -2/(t^3)