What is the derivative of y=x-x^3 ?

The derivative of y=x-x^3 is 1-3x^2

What is the first derivative of y=x-x^3 ?

The first derivative of y=x-x^3 is 1-3x^2

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derivative of

y = x - x^{3}

1 - 3 x^{2}

Solution steps

\frac{d}{d x} (x - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d x}{d x} - \frac{d}{d x} (x^{3})

\frac{d x}{d x} = 1

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 1 - 3 x^{2}

\int \frac{x ^{2} - 5}{( x + 1 ) ^{3}} d x

\int_{0}^{π} 20 sin^{4} (x) d x

\int 3 x cos (3 x) d x

y^{^{'}} - 2 y = 3 e^{2 t}

\frac{d}{d x} (x^{2} + 15)

What is the derivative of y=x-x^3 ?
The derivative of y=x-x^3 is 1-3x^2
What is the first derivative of y=x-x^3 ?
The first derivative of y=x-x^3 is 1-3x^2