What is the integral from 0 to pi of 20sin^4(x) ?

The integral from 0 to pi of 20sin^4(x) is (15pi)/2

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integral from 0 to pi of 20sin^4(x)

\int_{0}^{π} 20 sin^{4} (x) d x

\frac{15 π}{2}

Decimal

23.56194 \dots

Solution steps

\int_{0}^{π} 20 sin^{4} (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 20 \cdot \int_{0}^{π} sin^{4} (x) d x

Apply Integral Reduction

= 20 (- [\frac{cos ( x ) sin ^{3} ( x )}{4}]_{0}^{π} + \frac{3}{4} \cdot \int_{0}^{π} sin^{2} (x) d x)

\int_{0}^{π} sin^{2} (x) d x = \frac{π}{2}

= 20 (- [\frac{cos ( x ) sin ^{3} ( x )}{4}]_{0}^{π} + \frac{3}{4} \cdot \frac{π}{2})

Simplify

20 (- [\frac{cos ( x ) sin ^{3} ( x )}{4}]_{0}^{π} + \frac{3}{4} \cdot \frac{π}{2}) : 20 (- [\frac{1}{4} sin^{3} (x) cos (x)]_{0}^{π} + \frac{3 π}{8})

= 20 (- [\frac{1}{4} sin^{3} (x) cos (x)]_{0}^{π} + \frac{3 π}{8})

Compute the boundaries:

0

= 20 (- 0 + \frac{3 π}{8})

Simplify

= \frac{15 π}{2}

\int 3 x cos (3 x) d x

y^{^{'}} - 2 y = 3 e^{2 t}

\frac{d}{d x} (x^{2} + 15)

x \to - 2 lim (- 7)

\int (4 x + 3) (2 x^{2} + 3 x) d x

What is the integral from 0 to pi of 20sin^4(x) ?
The integral from 0 to pi of 20sin^4(x) is (15pi)/2