y-y^2+xy^'=0

Lösung

y - y^{2} + x y^{^{'}} = 0

y = \frac{1}{1 - c _{1} x}

Schritte zur Lösung

y - y^{2} + x y^{'} (x) = 0

Solve separable ODE:

y = \frac{1}{1 - c _{1} x}

y = \frac{1}{1 - c _{1} x}

e^{x} \frac{d y}{d x} + y^{3} = x y^{3}

y^{^{'}} = a y

\frac{d y}{d x} = x^{3} y^{4}

y^{^{'}} = \frac{1}{2} x 1 - 16 y^{2}

\frac{d y}{d x} = \frac{x}{3 - y}