(dy)/(dx)=x^3y^4

Lösung

\frac{d y}{d x} = x^{3} y^{4}

y = - 3 \frac{4}{3 ( x ^{4} + c _{1} )}

Schritte zur Lösung

\frac{d y}{d x} = x^{3} y^{4}

Solve separable ODE:

y = - 3 \frac{4}{3 ( x ^{4} + c _{1} )}

y = - 3 \frac{4}{3 ( x ^{4} + c _{1} )}

y^{^{'}} = \frac{1}{2} x 1 - 16 y^{2}

\frac{d y}{d x} = \frac{x}{3 - y}

\frac{d P}{d t} = k P (t)

\frac{d y}{d x} = - 10 x^{3} e^{y}

(1 + x) y^{^{'}} + y = 0