y^'= 1/2 xsqrt(1-16y^2)

Lösung

y^{^{'}} = \frac{1}{2} x 1 - 16 y^{2}

y = \frac{sin ( x ^{2} + c _{1} )}{4}

Schritte zur Lösung

y^{'} (x) = \frac{1}{2} x 1 - 16 y^{2}

Solve separable ODE:

y = \frac{sin ( x ^{2} + c _{1} )}{4}

y = \frac{sin ( x ^{2} + c _{1} )}{4}

\frac{d y}{d x} = \frac{x}{3 - y}

\frac{d P}{d t} = k P (t)

\frac{d y}{d x} = - 10 x^{3} e^{y}

(1 + x) y^{^{'}} + y = 0

\frac{d y}{d x} = \frac{- 3 x + 3 x y ^{2}}{y x ^{2} + 2 y}