What is the d/(dt)(3cos^6(t)) ?

The d/(dt)(3cos^6(t)) is -18cos^5(t)sin(t)

What is the first d/(dt)(3cos^6(t)) ?

The first d/(dt)(3cos^6(t)) is -18cos^5(t)sin(t)

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\frac{d}{d t} (3 cos^{6} (t))

- 18 cos^{5} (t) sin (t)

Solution steps

\frac{d}{d t} (3 cos^{6} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (cos^{6} (t))

Apply the chain rule:

6 (cos (t))^{5} \frac{d}{d t} (cos (t))

= 6 (cos (t))^{5} \frac{d}{d t} (cos (t))

\frac{d}{d t} (cos (t)) = - sin (t)

= 3 \cdot 6 (cos (t))^{5} (- sin (t))

Simplify

= - 18 cos^{5} (t) sin (t)

d er i v a t i v e f (x) = \frac{( x ^{3} + 4 x - 1 )}{x ^{2}}

d er i v a t i v e \frac{( 1 + 2 x + x ^{2} )}{e ^{x}}

d er i v a t i v e \frac{x ^{2}}{2 + 3 x}

d er i v a t i v e 4 x ln (2 x + 1)

\frac{d}{d q} (2600 - 13 q)

What is the d/(dt)(3cos^6(t)) ?
The d/(dt)(3cos^6(t)) is -18cos^5(t)sin(t)
What is the first d/(dt)(3cos^6(t)) ?
The first d/(dt)(3cos^6(t)) is -18cos^5(t)sin(t)