What is the first d/(dq)(2600-13q) ?

The first d/(dq)(2600-13q) is -13

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d/(dq)(2600-13q)

\frac{d}{d q} (2600 - 13 q)

- 13

Solution steps

\frac{d}{d q} (2600 - 13 q)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d q} (2600) - \frac{d}{d q} (13 q)

\frac{d}{d q} (2600) = 0

\frac{d}{d q} (13 q) = 13

= 0 - 13

Simplify

= - 13

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