integral of 3-0.01x+0.000006x^2

Lösung

\int 3 - 0.01 x + 0.000006 x^{2} d x

3 x - 0.005 x^{2} + 0.000002 x^{3} + C

Schritte zur Lösung

\int 3 - 0.01 x + 0.000006 x^{2} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 d x - \int 0.01 x d x + \int 0.000006 x^{2} d x

\int 3 d x = 3 x

\int 0.01 x d x = 0.005 x^{2}

\int 0.000006 x^{2} d x = 0.000002 x^{3}

= 3 x - 0.005 x^{2} + 0.000002 x^{3}

Füge eine Konstante zur Lösung hinzu

= 3 x - 0.005 x^{2} + 0.000002 x^{3} + C

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