What is (\partial ^2)/(\partial y^2)(x^2-e^{y^2}) ?

The answer to (\partial ^2)/(\partial y^2)(x^2-e^{y^2}) is -2(2e^{y^2}y^2+e^{y^2})

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(\partial ^2)/(\partial y^2)(x^2-e^{y^2})

\frac{\partial ^{2}}{\partial y ^{2}} (x^{2} - e^{y^{2}})

- 2 (2 e^{y^{2}} y^{2} + e^{y^{2}})

Solution steps

\frac{\partial ^{2}}{\partial y ^{2}} (x^{2} - e^{y^{2}})

\frac{\partial}{\partial y} (x^{2} - e^{y^{2}}) = - 2 e^{y^{2}} y

= \frac{\partial}{\partial y} (- 2 e^{y^{2}} y)

\frac{\partial}{\partial y} (- 2 e^{y^{2}} y) = - 2 (2 e^{y^{2}} y^{2} + e^{y^{2}})

= - 2 (2 e^{y^{2}} y^{2} + e^{y^{2}})

\int_{0}^{\frac{π}{8}} x tan^{2} (2 x) d x

\int \frac{1}{4 u ^{2} + 9 - 41 u} d u

- sin (2 t)

\int \frac{1}{5 + 4 cos ( x )} d x

n = 6 \sum \infty \frac{5 ^{n}}{1 4 ^{n}}

What is (\partial ^2)/(\partial y^2)(x^2-e^{y^2}) ?
The answer to (\partial ^2)/(\partial y^2)(x^2-e^{y^2}) is -2(2e^{y^2}y^2+e^{y^2})