What is the sum from n=6 to infinity of (5^n)/(14^n) ?

The sum from n=6 to infinity of (5^n)/(14^n) is converges

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sum from n=6 to infinity of (5^n)/(14^n)

n = 6 \sum \infty \frac{5 ^{n}}{1 4 ^{n}}

converges

Solution steps

n = 6 \sum \infty \frac{5 ^{n}}{1 4 ^{n}}

n \to \infty lim (n (\frac{\frac{5 ^{n}}{1 4 ^{n}}}{\frac{5 ^{n + 1}}{1 4 ^{n + 1}}} - 1)) = \infty

L > 1,

by the Raabe's test

= converges

\frac{d}{d x} (\frac{x}{x - 10})

ln (1 - z)

\int 3 x^{2} - 24 x + 48 d x

\int \frac{x ^{2} - 7 x - 12}{x ( x ^{2} + 3 x + 3 )} d x

\frac{d}{d x} (3 x^{4} - 8 x^{3} + 2)

What is the sum from n=6 to infinity of (5^n)/(14^n) ?
The sum from n=6 to infinity of (5^n)/(14^n) is converges