What is the derivative of 3x^4-8x^3+2 ?

The derivative of 3x^4-8x^3+2 is 12x^3-24x^2

What is the first derivative of 3x^4-8x^3+2 ?

The first derivative of 3x^4-8x^3+2 is 12x^3-24x^2

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\frac{d}{d x} (3 x^{4} - 8 x^{3} + 2)

12 x^{3} - 24 x^{2}

Solution steps

\frac{d}{d x} (3 x^{4} - 8 x^{3} + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{4}) - \frac{d}{d x} (8 x^{3}) + \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{4}) = 12 x^{3}

\frac{d}{d x} (8 x^{3}) = 24 x^{2}

\frac{d}{d x} (2) = 0

= 12 x^{3} - 24 x^{2} + 0

Simplify

= 12 x^{3} - 24 x^{2}

What is the derivative of 3x^4-8x^3+2 ?
The derivative of 3x^4-8x^3+2 is 12x^3-24x^2
What is the first derivative of 3x^4-8x^3+2 ?
The first derivative of 3x^4-8x^3+2 is 12x^3-24x^2