What is laplacetransform-sin(2t) ?

The answer to laplacetransform-sin(2t) is -2/(s^2+4)

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laplacetransform-sin(2t)

laplace transform

- sin (2 t)

- \frac{2}{s ^{2} + 4}

Solution steps

L {- sin (2 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - L {sin (2 t)}

L {sin (2 t)} : \frac{2}{s ^{2} + 4}

= - \frac{2}{s ^{2} + 4}

\int \frac{1}{5 + 4 cos ( x )} d x

n = 6 \sum \infty \frac{5 ^{n}}{1 4 ^{n}}

\frac{d}{d x} (\frac{x}{x - 10})

ln (1 - z)

\int 3 x^{2} - 24 x + 48 d x

What is laplacetransform-sin(2t) ?
The answer to laplacetransform-sin(2t) is -2/(s^2+4)