What are the solutions to the equation 3(x+4)^2=-27 ?

The solutions to the equation 3(x+4)^2=-27 are x=3i-4,x=-3i-4

Find the zeros of 3(x+4)^2=-27

The zeros of 3(x+4)^2=-27 are x=3i-4,x=-3i-4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (x + 4)^{2} = - 27

x = 3 i - 4, x = - 3 i - 4

Solution steps

3 (x + 4)^{2} = - 27

Divide both sides by

3

(x + 4)^{2} = - 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 4 = - 9 : x = 3 i - 4

Solve

x + 4 = - - 9 : x = - 3 i - 4

The solutions to the quadratic equation are:

x = 3 i - 4, x = - 3 i - 4

- (x + 5) - 6 x \leq 2 x - 5

y^{2} - 10 y + 25

2 x^{3} + 14 x^{2} + 10 x

- 8 (8 x - 2) = 3 x + 16

4 x^{2} - 18 = 0

What are the solutions to the equation 3(x+4)^2=-27 ?
The solutions to the equation 3(x+4)^2=-27 are x=3i-4,x=-3i-4
Find the zeros of 3(x+4)^2=-27
The zeros of 3(x+4)^2=-27 are x=3i-4,x=-3i-4