What is (4yz^2)/(3xy^4z)*(15x^2y)/(8x^3yz) ?

The solution to (4yz^2)/(3xy^4z)*(15x^2y)/(8x^3yz) is 5/(2x^2y^3)

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simplify (4yz^2)/(3xy^4z)*(15x^2y)/(8x^3yz)

simplify

\frac{4 y z ^{2}}{3 x y ^{4} z} \cdot \frac{15 x ^{2} y}{8 x ^{3} yz}

\frac{5}{2 x ^{2} y ^{3}}

Solution steps

\frac{4 y z ^{2}}{3 x y ^{4} z} \cdot \frac{15 x ^{2} y}{8 x ^{3} yz}

Cancel

\frac{4 y z ^{2}}{3 x y ^{4} z} : \frac{4 z}{3 x y ^{3}}

= \frac{4 z}{3 x y ^{3}} \cdot \frac{15 x ^{2} y}{8 x ^{3} yz}

Cancel

\frac{15 x ^{2} y}{8 x ^{3} yz} : \frac{15}{8 x z}

= \frac{4 z}{3 x y ^{3}} \cdot \frac{15}{8 x z}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 z \cdot 15}{3 x y ^{3} \cdot 8 x z}

Apply exponent rule:

aa = a^{2}

xx = x^{2}

= \frac{4 z \cdot 15}{3 x ^{2} y ^{3} \cdot 8 z}

Cancel the common factor:

z

= \frac{4 \cdot 15}{3 x ^{2} y ^{3} \cdot 8}

Factor the number:

8 = 4 \cdot 2

= \frac{4 \cdot 15}{3 x ^{2} y ^{3} \cdot 4 \cdot 2}

Cancel the common factor:

4

= \frac{15}{3 x ^{2} y ^{3} \cdot 2}

Factor the number:

15 = 3 \cdot 5

= \frac{3 \cdot 5}{3 x ^{2} y ^{3} \cdot 2}

Cancel the common factor:

3

= \frac{5}{x ^{2} y ^{3} \cdot 2}

= \frac{5}{2 x ^{2} y ^{3}}

3 \geq 2 x

6 x + 5 = 23

2 x^{2} + 9 x - 5 < 0

(y^{4} x^{\frac{4}{3}})^{\frac{3}{4}}

12 x^{2} - 48 x + 48 = 0

What is (4yz^2)/(3xy^4z)*(15x^2y)/(8x^3yz) ?
The solution to (4yz^2)/(3xy^4z)*(15x^2y)/(8x^3yz) is 5/(2x^2y^3)