What are the solutions to the equation 12x^2-48x+48=0 ?

The solutions to the equation 12x^2-48x+48=0 are x=2

Find the zeros of 12x^2-48x+48=0

The zeros of 12x^2-48x+48=0 are x=2

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12 x^{2} - 48 x + 48 = 0

x = 2

Solution steps

12 x^{2} - 48 x + 48 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 12 \cdot 48}{2 \cdot 12}

(- 48)^{2} - 4 \cdot 12 \cdot 48 = 0

x_{1, 2} = \frac{- ( - 48 ) \pm 0}{2 \cdot 12}

x = \frac{- ( - 48 )}{2 \cdot 12}

\frac{- ( - 48 )}{2 \cdot 12} = 2

x = 2

The solution to the quadratic equation is:

x = 2

3 x^{2} = 5 x + 2

2 (x - 4) < 5 x + 4

(- \frac{1}{3})^{2} + 1

\frac{1}{3} + \frac{5}{6} - \frac{2}{9}

- x^{2} = - 36

What are the solutions to the equation 12x^2-48x+48=0 ?
The solutions to the equation 12x^2-48x+48=0 are x=2
Find the zeros of 12x^2-48x+48=0
The zeros of 12x^2-48x+48=0 are x=2