What is ((x/(9y)+1/(6xy)))/((1/(3xy))) ?

The solution to ((x/(9y)+1/(6xy)))/((1/(3xy))) is (x^2)/3+1/2

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simplify ((x/(9y)+1/(6xy)))/((1/(3xy)))

simplify

\frac{( \frac{x}{9 y} + \frac{1}{6 x y} )}{( \frac{1}{3 x y} )}

\frac{x ^{2}}{3} + \frac{1}{2}

Solution steps

\frac{\frac{x}{9 y} + \frac{1}{6 x y}}{\frac{1}{3 x y}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{( \frac{x}{9 y} + \frac{1}{6 x y} ) \cdot 3 x y}{1}

Cancel

\frac{( \frac{x}{9 y} + \frac{1}{6 x y} ) \cdot 3 x y}{1} : \frac{x ^{2}}{3} + \frac{1}{2}

= \frac{x ^{2}}{3} + \frac{1}{2}

- 7 n^{- 4} \cdot 5 n^{- 2}

\frac{3}{48}

2 X = 6

(9 - λ) \cdot (4 - λ) = 0

(∣ x + 4 ∣^{2} - 25) \cdot (x^{2} - 9) \leq 0

What is ((x/(9y)+1/(6xy)))/((1/(3xy))) ?
The solution to ((x/(9y)+1/(6xy)))/((1/(3xy))) is (x^2)/3+1/2