What are the solutions to the equation 14n^2+41n+15=0 ?

The solutions to the equation 14n^2+41n+15=0 are n=-3/7 ,n=-5/2

Find the zeros of 14n^2+41n+15=0

The zeros of 14n^2+41n+15=0 are n=-3/7 ,n=-5/2

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14 n^{2} + 41 n + 15 = 0

n = - \frac{3}{7}, n = - \frac{5}{2}

Decimal Notation

n = - 0.42857 \dots, n = - 2.5

Solution steps

14 n^{2} + 41 n + 15 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 41 \pm 4 1 ^{2} - 4 \cdot 14 \cdot 15}{2 \cdot 14}

4 1^{2} - 4 \cdot 14 \cdot 15 = 29

n_{1, 2} = \frac{- 41 \pm 29}{2 \cdot 14}

Separate the solutions

n_{1} = \frac{- 41 + 29}{2 \cdot 14}, n_{2} = \frac{- 41 - 29}{2 \cdot 14}

n = \frac{- 41 + 29}{2 \cdot 14} : - \frac{3}{7}

n = \frac{- 41 - 29}{2 \cdot 14} : - \frac{5}{2}

The solutions to the quadratic equation are:

n = - \frac{3}{7}, n = - \frac{5}{2}

2 x^{2} - 12 x - 65 = 45

2 (- 2) - 2 y = - 2

\frac{25}{2}

2 0^{\frac{3}{2}}

\frac{x}{x + 1}

What are the solutions to the equation 14n^2+41n+15=0 ?
The solutions to the equation 14n^2+41n+15=0 are n=-3/7 ,n=-5/2
Find the zeros of 14n^2+41n+15=0
The zeros of 14n^2+41n+15=0 are n=-3/7 ,n=-5/2