What are the solutions to the equation 2x^2-12x-65=45 ?

The solutions to the equation 2x^2-12x-65=45 are x=11,x=-5

Find the zeros of 2x^2-12x-65=45

The zeros of 2x^2-12x-65=45 are x=11,x=-5

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2 x^{2} - 12 x - 65 = 45

x = 11, x = - 5

Solution steps

2 x^{2} - 12 x - 65 = 45

Move

45

to the left side

2 x^{2} - 12 x - 110 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 2 ( - 110 )}{2 \cdot 2}

(- 12)^{2} - 4 \cdot 2 (- 110) = 32

x_{1, 2} = \frac{- ( - 12 ) \pm 32}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 32}{2 \cdot 2}, x_{2} = \frac{- ( - 12 ) - 32}{2 \cdot 2}

x = \frac{- ( - 12 ) + 32}{2 \cdot 2} : 11

x = \frac{- ( - 12 ) - 32}{2 \cdot 2} : - 5

The solutions to the quadratic equation are:

x = 11, x = - 5

2 (- 2) - 2 y = - 2

\frac{25}{2}

2 0^{\frac{3}{2}}

\frac{x}{x + 1}

∣ 3 x + 2 ∣ \geq 6

What are the solutions to the equation 2x^2-12x-65=45 ?
The solutions to the equation 2x^2-12x-65=45 are x=11,x=-5
Find the zeros of 2x^2-12x-65=45
The zeros of 2x^2-12x-65=45 are x=11,x=-5