v=vit+1/2 gt^2

解答

v = v i t + \frac{1}{2} g t^{2}

(v = 0, t = 0)

求解步骤

v = v i t + \frac{1}{2} g t^{2}

将

v

改写成标准复数形式:

v + 0 i

v + 0 i = v i t + \frac{1}{2} g t^{2}

将

v i t + \frac{1}{2} g t^{2}

改写成标准复数形式:

\frac{g t ^{2}}{2} + v t i

v + 0 i = \frac{g t ^{2}}{2} + v t i

复数仅在实部和虚部均相等时才相等改写为方程组:

[v = \frac{g t ^{2}}{2} 0 = v t]

[v = \frac{g t ^{2}}{2} 0 = v t] : (v = 0, t = 0)

(v = 0, t = 0)

z^{2} - (2 + i) z + 3 + i = 0

2 a - bi = \frac{1}{3 - 4 i}

2 x - 3 y i = 14 + 12 i

z^{2} + (1 + i) z + i = 0

s i P (x) = 2 x - 1, Q (x) = x + 3