w=(p+4i)/(1+ip)

解答

w = \frac{p + 4 i}{1 + i p}

(p = 2, w = 2 p = - 2, w = - 2)

求解步骤

w = \frac{p + 4 i}{1 + i p}

在两边乘以

1 + i p

w (1 + i p) = \frac{p + 4 i}{1 + i p} (1 + i p)

乘开

w + i wp = p + 4 i

复数仅在实部和虚部均相等时才相等改写为方程组:

[w = p wp = 4]

[w = p wp = 4] : (p = 2, w = 2 p = - 2, w = - 2)

(p = 2, w = 2 p = - 2, w = - 2)

25 x^{2} + 60 x + 37 = 0 a + bia + bi

∣ Z + 1 ∣ = (Z + 2) (1 + i)

1 + 2 i = z + \frac{i}{z}

(x - y) + 3 i = 2 + y i

2 x + 2 y = 2 x + 2 y i + 10, x, y