4+x+3i=8-(y+1)i

解答

4 + x + 3 i = 8 - (y + 1) i

x = 4, y = - 4

求解步骤

4 + x + 3 i = 8 - (y + 1) i

将

8 - (y + 1) i

改写成标准复数形式:

8 + (- y - 1) i

4 + x + 3 i = 8 + (- y - 1) i

复数仅在实部和虚部均相等时才相等改写为方程组:

[4 + x = 8 3 = - y - 1]

[4 + x = 8 3 = - y - 1] : x = 4, y = - 4

x = 4, y = - 4

- \frac{1}{z - i} + 1 - i - z = 0

- 3 + 4 i = (x + i y)^{2}

i (x) = 3 - \frac{4}{2 - x}

x + y i = 9 + 2 i

z^{2} + (- 2 + 3 i) z - 2 - 4 i = 0