2^x*2^{x-2}=sqrt(2)

解答

2^{x} \cdot 2^{x - 2} = 2

x = \frac{5}{4}

十进制

x = 1.25

求解步骤

2^{x} \cdot 2^{x - 2} = 2

使用指数运算法则

2 x - 2 = \frac{1}{2}

解

2 x - 2 = \frac{1}{2} : x = \frac{5}{4}

x = \frac{5}{4}

4 e^{2 x} = 9

2^{20 x + 10} = 4^{10 x + 5}

7^{x + 4} = 8^{x}

7^{3 x^{2}} = 4 9^{6 x + 2}

9^{x} - 4 = 3^{x + 1}