2^{x+1}=3^{x-5}

Lösung

2^{x + 1} = 3^{x - 5}

x = \frac{ln ( 486 )}{ln ( 3 ) - ln ( 2 )}

Dezimale

x = 15.25706 \dots

Schritte zur Lösung

2^{x + 1} = 3^{x - 5}

Wende Exponentenregel an

(x + 1) ln (2) = (x - 5) ln (3)

Löse

(x + 1) ln (2) = (x - 5) ln (3) : x = \frac{ln ( 486 )}{ln ( 3 ) - ln ( 2 )}

x = \frac{ln ( 486 )}{ln ( 3 ) - ln ( 2 )}

2. 2^{x} = 8

3^{x^{2}} = 9^{- x + 12}

3^{- x} = \frac{1}{3 ^{x}}

4^{2 x} - 68 \cdot 4^{x} + 256 = 0

so l v e f or x, 4^{3 x} = 4^{x - 1}