3^{x^2}=9^{-x+12}

Lösung

3^{x^{2}} = 9^{- x + 12}

x = 4, x = - 6

Schritte zur Lösung

3^{x^{2}} = 9^{- x + 12}

Wende Exponentenregel an

x^{2} = 2 (- x + 12)

Löse

x^{2} = 2 (- x + 12) : x = 4, x = - 6

x = 4, x = - 6

3^{- x} = \frac{1}{3 ^{x}}

4^{2 x} - 68 \cdot 4^{x} + 256 = 0

so l v e f or x, 4^{3 x} = 4^{x - 1}

3 = 5^{x}

so l v e f or x, 2^{x + 3^{y}} = 11