32^{x-2}=8^{(x+6)/3}

Lösung

3 2^{x - 2} = 8^{\frac{x + 6}{3}}

x = 4

Schritte zur Lösung

3 2^{x - 2} = 8^{\frac{x + 6}{3}}

Wende Exponentenregel an

5 (x - 2) = x + 6

Löse

5 (x - 2) = x + 6 : x = 4

x = 4

(3^{x})^{2} = 9^{x}

1 6^{x} = \frac{1}{2}

9^{x} = 3^{x + 1} + 4

ln (e^{8 x}) = 96

so l v e f or t, 40 = 12 0^{0.4 t} + 25