faktorisieren 27^3+8

Lösung

faktorisieren

2 7^{3} + 8

19691

Schritte zur Lösung

2 7^{3} + 8

2 7^{3} = 19683

= 19683 + 8

Addiere die Zahlen:

19683 + 8 = 19691

= 19691

f (x) = 1 + (sin (3 x^{2}))^{2}

f a c t or f (x) ln (x)

f a c t or cos^{2} (x) + 2 cos (x) + 1

f a c t or (5 x + 3)^{3} + (x - 5)^{3}

f a c t or cos^{2} (x) + 2 cos (x) - 3