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Frequently Asked Questions (FAQ)
What are the solutions to the equation (3y+2)^2+10=-18 ?
- The solutions to the equation (3y+2)^2+10=-18 are y=-2/3+i(2sqrt(7))/3 ,y=-2/3-i(2sqrt(7))/3
Find the zeros of (3y+2)^2+10=-18
- The zeros of (3y+2)^2+10=-18 are y=-2/3+i(2sqrt(7))/3 ,y=-2/3-i(2sqrt(7))/3