x^2-(2sqrt(3)+1)x+2sqrt(3)=0

解答

x^{2} - (23 + 1) x + 23 = 0

x = 23, x = 1

十进制

x = 3.46410 \dots, x = 1

求解步骤

x^{2} - (23 + 1) x + 23 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 2 3 - 1 ) \pm ( - 2 3 - 1 ) ^{2} - 4 \cdot 1 \cdot 2 3}{2 \cdot 1}

(- 23 - 1)^{2} - 4 \cdot 1 \cdot 23 = 23 - 1

x_{1, 2} = \frac{- ( - 2 3 - 1 ) \pm ( 2 3 - 1 )}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 2 3 - 1 ) + 2 3 - 1}{2 \cdot 1}, x_{2} = \frac{- ( - 2 3 - 1 ) - ( 2 3 - 1 )}{2 \cdot 1}

x = \frac{- ( - 2 3 - 1 ) + 2 3 - 1}{2 \cdot 1} : 23

x = \frac{- ( - 2 3 - 1 ) - ( 2 3 - 1 )}{2 \cdot 1} : 1

二次方程组的解是:

x = 23, x = 1

3 x^{2} + 18 x - 9 = 0

\frac{m ^{2}}{5} - \frac{m}{2} = \frac{3}{10}

(x + 3) (x - 3) - (x - 2)^{2} = 6 + x (x - 5)

- 3 l^{2} + 20 l + 100 = 0

3 (x^{2} - 2 x) = 8 (x - 2) + 8