3(2+3x)^2-9(2+3x)=0

Lösung

3 (2 + 3 x)^{2} - 9 (2 + 3 x) = 0

x = \frac{1}{3}, x = - \frac{2}{3}

Dezimale

x = 0.33333 \dots, x = - 0.66666 \dots

Schritte zur Lösung

3 (2 + 3 x)^{2} - 9 (2 + 3 x) = 0

Schreibe

3 (2 + 3 x)^{2} - 9 (2 + 3 x)

um:

27 x^{2} + 9 x - 6

27 x^{2} + 9 x - 6 = 0

Löse mit der quadratischen Formel

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 27 ( - 6 )}{2 \cdot 27}

9^{2} - 4 \cdot 27 (- 6) = 27

x_{1, 2} = \frac{- 9 \pm 27}{2 \cdot 27}

Trenne die Lösungen

x_{1} = \frac{- 9 + 27}{2 \cdot 27}, x_{2} = \frac{- 9 - 27}{2 \cdot 27}

x = \frac{- 9 + 27}{2 \cdot 27} : \frac{1}{3}

x = \frac{- 9 - 27}{2 \cdot 27} : - \frac{2}{3}

Die Lösungen für die quadratische Gleichung sind:

x = \frac{1}{3}, x = - \frac{2}{3}

(2 + t)^{2} + (9 + t)^{2} = 169

x^{2} - (n - 3) x + 16 = 0

7 x = 2 x^{2} - 4

so l v e f or x, x^{2} p^{2} + y^{2} q^{2} = z^{2}

6 x^{2} + 5 x = 1