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受欢迎的代数 >

m=(x+7)2+(x-10)(x-4)

解答

m = (x + 7) 2 + (x - 10) (x - 4)

解答

x = 6 + m - 18, x = 6 - m - 18

求解步骤

m = (x + 7) \cdot 2 + (x - 10) (x - 4)

展开

(x + 7) \cdot 2 + (x - 10) (x - 4) : x^{2} - 12 x + 54

m = x^{2} - 12 x + 54

交换两边

x^{2} - 12 x + 54 = m

将

m

para o lado esquerdo

x^{2} - 12 x + 54 - m = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( 54 - m )}{2 \cdot 1}

化简

(- 12)^{2} - 4 \cdot 1 \cdot (54 - m) : 2 m - 18

x_{1, 2} = \frac{- ( - 12 ) \pm 2 m - 18}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 12 ) + 2 m - 18}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 2 m - 18}{2 \cdot 1}

x = \frac{- ( - 12 ) + 2 m - 18}{2 \cdot 1} : 6 + m - 18

x = \frac{- ( - 12 ) - 2 m - 18}{2 \cdot 1} : 6 - m - 18

二次方程组的解是:

x = 6 + m - 18, x = 6 - m - 18

作图

流行的例子

12 x^{2} - 8 x - 15 = 0

1^2+2^2+3^2+n^2=(3.14)(n+1)(2n+1)

1^{2} + 2^{2} + 3^{2} + n^{2} = (3.14) (n + 1) (2 n + 1)

solvefor t,St+1=t^2+S

so l v e f or t, St + 1 = t^{2} + S

3 t (t + 2) = 0

solvefor x,r^2=(y-r)^2+(x/2)^2

so l v e f or x, r^{2} = (y - r)^{2} + (\frac{x}{2})^{2}